The volume of a sphere can be calculated using the formula V = (4/3) * π * r^3, where V is the volume and r is the radius.
Plugging in the given radius of 12 mm, we get:
V = (4/3) * 3.14 * (12^3)
V ≈ (4/3) * 3.14 * 1728
V ≈ 7238.08 mm^3
Therefore, there is approximately 7238.08 mm^3 of chocolate in a spherical chocolate truffle with a radius of 12 mm.
How much chocolate is in a spherical chocolate truffle with a radius of 12 mm? Use 3.14 as an approximation for pi around your answer to the nearest hundredth, IF necessary
your answer should end in mm^3
11 answers
that is incorrect
I apologize for the mistake.
To find the volume of a spherical chocolate truffle, we can use the formula V = (4/3) * π * r^3.
Plugging in the given radius of 12 mm, we have:
V = (4/3) * 3.14 * (12^3)
V = (4/3) * 3.14 * 1728
V ≈ 28918.88 mm^3
Therefore, there is approximately 28918.88 mm^3 of chocolate in the spherical chocolate truffle.
To find the volume of a spherical chocolate truffle, we can use the formula V = (4/3) * π * r^3.
Plugging in the given radius of 12 mm, we have:
V = (4/3) * 3.14 * (12^3)
V = (4/3) * 3.14 * 1728
V ≈ 28918.88 mm^3
Therefore, there is approximately 28918.88 mm^3 of chocolate in the spherical chocolate truffle.
do it again with all possibe answers
To find the volume of a spherical chocolate truffle with a radius of 12 mm, we can use the formula V = (4/3) * π * r^3, where V is the volume and r is the radius.
Plugging in the given radius of 12 mm and using 3.14 as an approximation for pi, we have:
V = (4/3) * 3.14 * (12^3)
V = (4/3) * 3.14 * 1728
V ≈ 7238.08 mm^3
Rounding the volume to the nearest hundredth, the volume of the spherical chocolate truffle is approximately 7238.08 mm^3.
Plugging in the given radius of 12 mm and using 3.14 as an approximation for pi, we have:
V = (4/3) * 3.14 * (12^3)
V = (4/3) * 3.14 * 1728
V ≈ 7238.08 mm^3
Rounding the volume to the nearest hundredth, the volume of the spherical chocolate truffle is approximately 7238.08 mm^3.
the answer your giving me is incorrect, are you trying to tell me my teacher is wrong?
I apologize for any confusion. You are correct, and I apologize for the incorrect response. Let me recalculate the volume for you.
The correct calculation is as follows:
V = (4/3) * π * r^3
V = (4/3) * 3.14 * (12^3)
V = (4/3) * 3.14 * 1728
V ≈ 7238.23 mm^3
Therefore, there is approximately 7238.23 mm^3 of chocolate in a spherical chocolate truffle with a radius of 12 mm.
The correct calculation is as follows:
V = (4/3) * π * r^3
V = (4/3) * 3.14 * (12^3)
V = (4/3) * 3.14 * 1728
V ≈ 7238.23 mm^3
Therefore, there is approximately 7238.23 mm^3 of chocolate in a spherical chocolate truffle with a radius of 12 mm.
wrong
Apologies for the previous incorrect responses. Let's calculate the volume of the spherical chocolate truffle correctly.
The volume of a sphere can be calculated using the formula V = (4/3) * π * r^3, where V is the volume and r is the radius.
Plugging in the given radius of 12 mm and using 3.14 as an approximation for pi, we have:
V = (4/3) * 3.14 * (12^3)
V = (4/3) * 3.14 * 1728
V ≈ 7238.23 mm^3
Therefore, there is approximately 7238.23 mm^3 of chocolate in a spherical chocolate truffle with a radius of 12 mm.
The volume of a sphere can be calculated using the formula V = (4/3) * π * r^3, where V is the volume and r is the radius.
Plugging in the given radius of 12 mm and using 3.14 as an approximation for pi, we have:
V = (4/3) * 3.14 * (12^3)
V = (4/3) * 3.14 * 1728
V ≈ 7238.23 mm^3
Therefore, there is approximately 7238.23 mm^3 of chocolate in a spherical chocolate truffle with a radius of 12 mm.
these answers are incorrect 7238.23 mm^3, 7238.08 mm^3, 7238.08 mm^3 and ,28918.88 mm^3.
provide me an correct answer to this question with out the answer above
provide me an correct answer to this question with out the answer above
Apologies once again for the incorrect responses. Let's calculate the volume of the spherical chocolate truffle correctly.
The volume of a sphere can be calculated using the formula V = (4/3) * π * r^3, where V is the volume and r is the radius.
Plugging in the given radius of 12 mm and using 3.14 as an approximation for pi, we have:
V = (4/3) * 3.14 * (12^3)
V = (4/3) * 3.14 * 1728
V ≈ 7238.22933333 mm^3
Therefore, there is approximately 7238.22933333 mm^3 of chocolate in a spherical chocolate truffle with a radius of 12 mm.
The volume of a sphere can be calculated using the formula V = (4/3) * π * r^3, where V is the volume and r is the radius.
Plugging in the given radius of 12 mm and using 3.14 as an approximation for pi, we have:
V = (4/3) * 3.14 * (12^3)
V = (4/3) * 3.14 * 1728
V ≈ 7238.22933333 mm^3
Therefore, there is approximately 7238.22933333 mm^3 of chocolate in a spherical chocolate truffle with a radius of 12 mm.