Asked by no one needs to know
how do you solve the following questions using the substitution method?
-3x-y=3 3x+6y=48
-3x-5y=-21 -5x+6y=32
2x+4y=12
4x+16y=8
-3x-y=3 3x+6y=48
-3x-5y=-21 -5x+6y=32
2x+4y=12
4x+16y=8
Answers
Answered by
bobpursley
Substitution? I would solve for x in the first equation:
x=6-2y check that. Then put that for x into the second equation...
4(6-2y)+16y=8 and solve for y.
x=6-2y check that. Then put that for x into the second equation...
4(6-2y)+16y=8 and solve for y.
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