What are the coordinates of the minimum point for the square root function that relates to the quadratic function f(x)=1/2(x−11)^2+4 ?(1 point)

Question

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Answer 1

The function you provided, \( f(x) = \frac{1}{2}(x - 11)^2 + 4 \), is a quadratic function in vertex form \( f(x) = a(x - h)^2 + k \), where \((h, k)\) is the vertex of the parabola.

In this case:

• \( h = 11 \)
• \( k = 4 \)

The vertex, which represents the minimum point of the quadratic function since it opens upwards (as the coefficient of \((x - h)^2\) is positive), is at the coordinates:

\[ (11, 4) \]

Thus, the coordinates of the minimum point are:

\[ (11, 4) \]