Question

Question
What are the coordinates of the minimum point for the square root function that relates to the quadratic function f(x)=12(x−11)2+4
?(1 point)
(
,
)

Answer 1

To find the coordinates of the minimum point for the quadratic function \( f(x) = 12(x - 11)^2 + 4 \), we can identify the vertex of the parabola.

The general form of a quadratic function in vertex form is given by:
\[
f(x) = a(x - h)^2 + k
\]
where \( (h, k) \) is the vertex of the parabola.

In your function:
- \( a = 12 \)
- \( h = 11 \)
- \( k = 4 \)

Since the coefficient \( a \) is positive (12), the parabola opens upwards, and the vertex represents the minimum point.

Thus, the coordinates of the minimum point are:
\[
(h, k) = (11, 4)
\]

So the answer is:
\[
(11, 4)
\]