To determine which expressions are equivalent to the original expression \((3x−8)+(2x+5)−(4x−8)\), we need to simplify the original expression first.
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Distributing and combining like terms:
- Start with \((3x - 8) + (2x + 5) - (4x - 8)\).
- This can be rewritten as: \[ 3x - 8 + 2x + 5 - 4x + 8 \]
- Now, combine like terms:
- \(3x + 2x - 4x = (3 + 2 - 4)x = 1x = x\)
- \(-8 + 5 + 8 = -8 + 13 = 5\)
So, simplifying gives: \[ x + 5 \]
Now, let's analyze the responses:
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\(3x−8+2x+5−4x−8\): This is equivalent (it's just a rearrangement of the original expression).
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\(3x−8+2x+5−4x+8\): This is not equivalent because it changes \(-8\) to \(+8\) (which alters the constant term).
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\(3x+2x−4x−8+5+8\): This is equivalent after simplification (same terms as above).
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\(x−13+8\): This is not equivalent since it simplifies to \(x - 5\), not \(x + 5\).
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\(x−21\): This is not equivalent as it is different from \(x + 5\).
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\(x+5\): This is equivalent.
Based on this analysis, the equivalent expressions are:
- \(3x−8+2x+5−4x−8\)
- \(3x+2x−4x−8+5+8\)
- \(x+5\)
Thus, the selected responses are:
- a (3x−8+2x+5−4x−8)
- c (3x+2x−4x−8+5+8)
- g (x+5)