Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Solve the inequality and graph the solution. v+1 3 ≥ – 1 Plot the endpoints. Select an endpoint to change it from closed to ope...Asked by evergreen
Solve the inequality and graph the solution.
n+9<10
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
n+9<10
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve the inequality \( n + 9 < 10 \), we first isolate \( n \):
1. Subtract 9 from both sides:
\[
n < 10 - 9
\]
\[
n < 1
\]
The solution to the inequality is \( n < 1 \).
### Graphing the Solution
1. **Endpoints:**
- The inequality \( n < 1 \) has a single endpoint at 1.
2. **Open or Closed Endpoint:**
- Since the inequality is strictly less than (\(<\)), we use an open circle at 1 to indicate that 1 is not included in the solution.
3. **Middle of the Segment/Ray to Delete:**
- The solution includes all values less than 1; therefore, we indicate the region to the left of 1. We will keep this entire ray.
### Final Graph:
- Place an **open circle** at 1.
- Shade the area to the left of 1, indicating all the values that are less than 1.
```
<------------------(1)---------------->
```
Here, the line extends infinitely to the left of the open circle at 1, indicating that all numbers less than 1 are included in the solution set.
1. Subtract 9 from both sides:
\[
n < 10 - 9
\]
\[
n < 1
\]
The solution to the inequality is \( n < 1 \).
### Graphing the Solution
1. **Endpoints:**
- The inequality \( n < 1 \) has a single endpoint at 1.
2. **Open or Closed Endpoint:**
- Since the inequality is strictly less than (\(<\)), we use an open circle at 1 to indicate that 1 is not included in the solution.
3. **Middle of the Segment/Ray to Delete:**
- The solution includes all values less than 1; therefore, we indicate the region to the left of 1. We will keep this entire ray.
### Final Graph:
- Place an **open circle** at 1.
- Shade the area to the left of 1, indicating all the values that are less than 1.
```
<------------------(1)---------------->
```
Here, the line extends infinitely to the left of the open circle at 1, indicating that all numbers less than 1 are included in the solution set.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.