Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Solve the inequality and graph the solution. v+1 3 ≥ – 1 Plot the endpoints. Select an endpoint to change it from closed to ope...Asked by evergreen
Solve the inequality and graph the solution.
14≥
–
2(a–10)
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
14≥
–
2(a–10)
Plot the endpoints. Select an endpoint to change it from closed to open. Select the middle of the segment, ray, or line to delete it.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve the inequality \( 14 \geq -2(a - 10) \), we will first simplify the expression on the right side.
1. Distribute the \(-2\) on the right side:
\[
14 \geq -2a + 20
\]
2. Next, we can isolate \(a\) by subtracting \(20\) from both sides:
\[
14 - 20 \geq -2a \quad \Rightarrow \quad -6 \geq -2a
\]
3. Now divide both sides by \(-2\). Remember that dividing by a negative number flips the inequality sign:
\[
\frac{-6}{-2} \leq a \quad \Rightarrow \quad 3 \leq a
\]
or equivalently,
\[
a \geq 3
\]
The solution to the inequality is \( a \geq 3 \).
### Graphing the Solution:
- The endpoint is \(3\).
- Since \(3\) is included in the solution (because the inequality is \(\geq\)), we will plot it as a closed circle.
- Since the solution indicates all values greater than or equal to \(3\), we will draw a solid line (or ray) extending to the right from \(3\).
### Steps to Graph:
1. Plot a closed circle (filled) at \(3\).
2. Draw a ray extending to the right from \(3\).
Thus, the graph represents all values of \(a\) that are greater than or equal to \(3\). The final graph would look like this:
```
<---o========================>
3
```
Where "o" is a closed circle at \(3\) and "=" indicates the ray extending to the right.
1. Distribute the \(-2\) on the right side:
\[
14 \geq -2a + 20
\]
2. Next, we can isolate \(a\) by subtracting \(20\) from both sides:
\[
14 - 20 \geq -2a \quad \Rightarrow \quad -6 \geq -2a
\]
3. Now divide both sides by \(-2\). Remember that dividing by a negative number flips the inequality sign:
\[
\frac{-6}{-2} \leq a \quad \Rightarrow \quad 3 \leq a
\]
or equivalently,
\[
a \geq 3
\]
The solution to the inequality is \( a \geq 3 \).
### Graphing the Solution:
- The endpoint is \(3\).
- Since \(3\) is included in the solution (because the inequality is \(\geq\)), we will plot it as a closed circle.
- Since the solution indicates all values greater than or equal to \(3\), we will draw a solid line (or ray) extending to the right from \(3\).
### Steps to Graph:
1. Plot a closed circle (filled) at \(3\).
2. Draw a ray extending to the right from \(3\).
Thus, the graph represents all values of \(a\) that are greater than or equal to \(3\). The final graph would look like this:
```
<---o========================>
3
```
Where "o" is a closed circle at \(3\) and "=" indicates the ray extending to the right.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.