To find the volume of a basketball with a diameter of 9 inches, we can use the formula for the volume of a sphere:
\[ V = \frac{4}{3} \pi r^3 \]
First, we need to find the radius. The radius \( r \) is half of the diameter. So, for a diameter of 9 inches:
\[ r = \frac{9}{2} = 4.5 \text{ inches} \]
Next, we substitute the radius into the volume formula and use \( \pi \approx 3.14 \):
\[ V = \frac{4}{3} \times 3.14 \times (4.5)^3 \]
Now, calculate \( (4.5)^3 \):
\[ (4.5)^3 = 4.5 \times 4.5 \times 4.5 = 20.25 \times 4.5 = 91.125 \]
Now, substitute this value back into the volume formula:
\[ V = \frac{4}{3} \times 3.14 \times 91.125 \]
Calculate \( \frac{4}{3} \times 3.14 \):
\[ \frac{4}{3} \times 3.14 \approx 4.1867 \]
Now multiply:
\[ V \approx 4.1867 \times 91.125 \approx 381.5 \]
So, the volume of the basketball is approximately \( 381.5 \) cubic inches.
Thus, the answer is:
381.5 in.³
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