To find the volume of a sphere, you can use the formula:
\[ V = \frac{4}{3} \pi r^3 \]
where \( V \) is the volume and \( r \) is the radius of the sphere.
- First, find the radius of the basketball. The diameter is 9 inches, so the radius \( r \) is:
\[ r = \frac{d}{2} = \frac{9}{2} = 4.5 \text{ inches} \]
- Next, use the formula for the volume of the sphere, substituting \( r \) and using \( \pi \approx 3.14 \):
\[ V = \frac{4}{3} \times 3.14 \times (4.5)^3 \]
- Calculate \( (4.5)^3 \):
\[ (4.5)^3 = 4.5 \times 4.5 \times 4.5 = 91.125 \]
- Now substitute this back into the volume formula:
\[ V = \frac{4}{3} \times 3.14 \times 91.125 \]
- Calculate \(\frac{4}{3} \times 3.14\):
\[ \frac{4}{3} \times 3.14 \approx 4.18666667 \]
- Now multiply by \( 91.125 \):
\[ V \approx 4.18666667 \times 91.125 = 381.696 \]
- Finally, round to the nearest tenth:
\[ V \approx 381.7 \text{ in}^3 \]
Since this is not one of the response options, it seems the best option might be the closest available value from the choices given.
The answer is:
381.5 in.³