Volume of Spheres Quick Check

3 of 53 of 5 Items
Question
Use the formula for the volume of a sphere to solve the following problem.

How much air is needed to fill a basketball with a diameter of 9 inches? Use 3.14 as an approximation for pi. Round your answer to the nearest tenth.

(1 point)
Responses

190.8 in.3
190.8 inches cubed

113 in.3
113 inches cubed

3,052.1 in.3
3,052.1 inches cubed

381.5 in.3

1 answer

To find the volume of a sphere, you can use the formula:

\[ V = \frac{4}{3} \pi r^3 \]

where \( V \) is the volume and \( r \) is the radius of the sphere.

  1. First, find the radius of the basketball. The diameter is 9 inches, so the radius \( r \) is:

\[ r = \frac{d}{2} = \frac{9}{2} = 4.5 \text{ inches} \]

  1. Next, use the formula for the volume of the sphere, substituting \( r \) and using \( \pi \approx 3.14 \):

\[ V = \frac{4}{3} \times 3.14 \times (4.5)^3 \]

  1. Calculate \( (4.5)^3 \):

\[ (4.5)^3 = 4.5 \times 4.5 \times 4.5 = 91.125 \]

  1. Now substitute this back into the volume formula:

\[ V = \frac{4}{3} \times 3.14 \times 91.125 \]

  1. Calculate \(\frac{4}{3} \times 3.14\):

\[ \frac{4}{3} \times 3.14 \approx 4.18666667 \]

  1. Now multiply by \( 91.125 \):

\[ V \approx 4.18666667 \times 91.125 = 381.696 \]

  1. Finally, round to the nearest tenth:

\[ V \approx 381.7 \text{ in}^3 \]

Since this is not one of the response options, it seems the best option might be the closest available value from the choices given.

The answer is:

381.5 in.³

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