Question

A coin is tossed twice in a row what is the probability of tossing heads both times
A, 1/4
D, 1/2
C, 3/4
D, 1/1

Answer 1

To find the probability of tossing heads twice in a row with a fair coin, we can analyze the situation as follows:

1. The probability of tossing heads on the first toss is \( \frac{1}{2} \).
2. The probability of tossing heads on the second toss is also \( \frac{1}{2} \).

Since the tosses are independent, we multiply the probabilities of the two events:

\[
P(\text{Heads on first toss}) \times P(\text{Heads on second toss}) = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}
\]

Therefore, the probability of tossing heads both times is \( \frac{1}{4} \), which corresponds to option A.