Asked by Algebra Probability
A coin is tossed twice.
What is the probability of tossing heads, and then tails, given that the coin has already shown heads in the first toss?
What is the probability of tossing heads, and then tails, given that the coin has already shown heads in the first toss?
Answers
Answered by
Steve
that would be P(tails) on the 2nd toss: 1/2
Answered by
Algebra Probability
Hey Steve, thanks! I was wondering though why I would of gotten 1/4 when I did the math the first time?
Answered by
PsyDAG
P(heads) = 1/2
P(tails) = 1/2
If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
P(heads) * P(tails) = 1/2 * 1/2 = 1/4
However, the toss of heads was already completed.
P(tails) = 1/2
If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
P(heads) * P(tails) = 1/2 * 1/2 = 1/4
However, the toss of heads was already completed.
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