A coin is tossed twice.
What is the probability of tossing heads, and then tails, given that the coin has already shown heads in the first toss?
3 answers
that would be P(tails) on the 2nd toss: 1/2
Hey Steve, thanks! I was wondering though why I would of gotten 1/4 when I did the math the first time?
P(heads) = 1/2
P(tails) = 1/2
If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
P(heads) * P(tails) = 1/2 * 1/2 = 1/4
However, the toss of heads was already completed.
P(tails) = 1/2
If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
P(heads) * P(tails) = 1/2 * 1/2 = 1/4
However, the toss of heads was already completed.