V1 = 68.4 m/s
X1 = 68.4 t
V2 = a (t-3.6)
X2 = (1/2) a (t-3.6)^2,
where a = 6.3 m/s^2
Set X1 = X2 and solve for t.
A race driver has made a pit stop to refuel. After refueling, he starts from rest and leaves the pit area with an acceleration whose magnitude is 6.3 m/s2; after 3.6 s he enters the main speedway. At the same instant, another car on the speedway and traveling at a constant velocity of 68.4 m/s overtakes and passes the entering car. The entering car maintains its acceleration. How much time is required for the entering car to catch up with the other car?
2 answers
can you give me the answer?
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