Asked by Sarah
A 1000 kg car pushes a 2000 kg truck that has a dead battery. When the drive steps on the accelerator, the drive wheels of the car push against the ground with a force of 4500 N.
a) What is the magnitude of the force of the car on the truck?
b) what is the magnitude of the force of the truck on the car?
a) What is the magnitude of the force of the car on the truck?
b) what is the magnitude of the force of the truck on the car?
Answers
Answered by
drwls
a) 4500 N = (1000 + 2000) a
Solve for a.
a = 1.5 m/s^2
F(car on truck) = Mtruck* a = 3000 N
F(car on truck) = 2000 kg*1.5 m/s^2
= 3000 N
b) Because of Newton's third law, the answers to a) and b) are the same.
Solve for a.
a = 1.5 m/s^2
F(car on truck) = Mtruck* a = 3000 N
F(car on truck) = 2000 kg*1.5 m/s^2
= 3000 N
b) Because of Newton's third law, the answers to a) and b) are the same.
Answered by
sedf
wqeqwe
Answered by
Adam
a) 4500 N = (1000 + 2000) a
Solve for a.
a = 1.5 m/s^2
F(car on truck) = Mtruck* a = 3000 N
F(car on truck) = 2000 kg*1.5 m/s^2
= 3000 N
b) Because of Newton's third law, the answers to a) and b) are the same.
Solve for a.
a = 1.5 m/s^2
F(car on truck) = Mtruck* a = 3000 N
F(car on truck) = 2000 kg*1.5 m/s^2
= 3000 N
b) Because of Newton's third law, the answers to a) and b) are the same.
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