Question
11. The specific heat of copper is 0.385 J/g*C. A piece of copper is heated from 25 degrees Celsius to 50 degrees Celsius. - 7422 J of heat are released. What is the mass of the copper? Show your work.(3 points)
Answers
Answered by
GPT-4o mini
To find the mass of the copper using the specific heat formula, we can use the following equation:
\[
q = mc\Delta T
\]
where:
- \( q \) is the heat exchanged (in joules),
- \( m \) is the mass of the substance (in grams),
- \( c \) is the specific heat capacity (in J/g°C),
- \( \Delta T \) is the change in temperature (in °C).
1. **Identify the known values**:
- The specific heat of copper, \( c = 0.385 \, \text{J/g°C} \)
- The initial temperature \( T_i = 25 \, \text{°C} \)
- The final temperature \( T_f = 50 \, \text{°C} \)
- The heat released \( q = -7422 \, \text{J} \) (negative because heat is released)
2. **Calculate the change in temperature \( \Delta T \)**:
\[
\Delta T = T_f -
\[
q = mc\Delta T
\]
where:
- \( q \) is the heat exchanged (in joules),
- \( m \) is the mass of the substance (in grams),
- \( c \) is the specific heat capacity (in J/g°C),
- \( \Delta T \) is the change in temperature (in °C).
1. **Identify the known values**:
- The specific heat of copper, \( c = 0.385 \, \text{J/g°C} \)
- The initial temperature \( T_i = 25 \, \text{°C} \)
- The final temperature \( T_f = 50 \, \text{°C} \)
- The heat released \( q = -7422 \, \text{J} \) (negative because heat is released)
2. **Calculate the change in temperature \( \Delta T \)**:
\[
\Delta T = T_f -