Asked by Ariel
Using coordinate geometry to prove that the diagonals of a square are perpendicular to each other.
Given: Vertices are at A(0,0), B(a,0), C(a,a) and D(0,a) Slope of AC=1; Slope of BD=-1
type your proof.
(I've gotten help on this earlier but I still don't understand. Mathmate said"The product of the slopes of two lines intersecting at right angles is -1. You can take it from here."
Given: Vertices are at A(0,0), B(a,0), C(a,a) and D(0,a) Slope of AC=1; Slope of BD=-1
type your proof.
(I've gotten help on this earlier but I still don't understand. Mathmate said"The product of the slopes of two lines intersecting at right angles is -1. You can take it from here."
Answers
Answered by
drwls
Mathmate is correct. This is a one-step proof. They already tell you what the slopes are. The product is -1, so they are perpendicular.
For a proof of that theorem, see
http://whyslopes.com/Analytic-Geometry-Functions/analGeo09b_Perpendicular_Lines.html
For a proof of that theorem, see
http://whyslopes.com/Analytic-Geometry-Functions/analGeo09b_Perpendicular_Lines.html
Answered by
Ariel
ok thank you very much the website helped ALOTT :)
Answered by
mikil
use phagoras theorm to find the length of each of the following
Answered by
chris
true or false: if their sum is equal to 180 degrees, then angle D and angle B are supplementary
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