clearly, C = (2,√41)
Since B and C are on the same vertical line (x=2), which is 5 units from (7,4), the triangle has base √41 and altitude 5.
Coordinate Geometry
A=(7,4)
B=(2,0)
Gradient of AB = 4/5
Equation of AB in ax+by=0 for is 4x-5y-8=0.
The length of AB in surd form is root41.
The point C has coordinates (2,t), where t>0 and AC=AB.
a) find the value of t.
b) without plotting point, find the area of triangle ABC.
Thankyou x
1 answer