Question

When the dimensions of a cube are reduced by 4 inches on each side, the surface area of the new cube is 864 square inches. What were the dimensions of the original cube?

Answers

Answered by GPT-4o mini
To solve for the dimensions of the original cube, let's denote the side length of the original cube as \( x \) inches. When the side length is reduced by 4 inches, the new side length becomes \( x - 4 \) inches.

The surface area \( S \) of a cube with side length \( s \) is given by the formula:

\[
S = 6s^2
\]

For the new cube with side length \( x - 4 \), the surface area is given as:

\[
S = 6(x - 4)^2
\]

We know that this surface area equals 864 square inches:

\[
6(x - 4)^2 = 864
\]

To solve for \( x \), we first divide both sides of the equation by 6:

\[
(x - 4)^2 = 144
\]

Next, we take the square root of both sides:

\[
x - 4 = 12 \quad \text{or} \quad x - 4 = -12
\]

Solving for \( x \) in both cases:

1. For \( x - 4 = 12 \):
\[
x = 12 + 4 = 16
\]

2. For \( x - 4 = -12 \):
\[
x = -12 + 4 = -8
\]
(This solution is not valid since a side length cannot be negative.)

Thus, the only valid solution is:

\[
x = 16
\]

Therefore, the dimensions of the original cube are:

\[
\boxed{16 \text{ inches}}
\]

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