Asked by Car
At 20oC, a 2.32 M aqueous solution of Ammonium Chloride has a density of 1.0344g/ml. WHat is the molality of Ammonium Chloride in the solution? The formula weight of NH4Cl is 53.50 g/mol??
I am not sure how to incorporate the density into the problem to come up with how to start. This is a sample of a question that will appear on CHM 152 test I have on MOnday. I just need to know where to begin in my steps please......HELP!!!!!
I am not sure how to incorporate the density into the problem to come up with how to start. This is a sample of a question that will appear on CHM 152 test I have on MOnday. I just need to know where to begin in my steps please......HELP!!!!!
Answers
Answered by
DrBob222
2.32 M = 2.32 moles NH4Cl/L solution.
2.32 moles NH4Cl = 2.32 x (53.5g/mol) = 124.12 g NH4Cl
mass of 1000 mL of the solution is 1000 x 1.0344 g/mL = 1034.4 g and 123.12 g is NH4Cl; therefore, the amount of water is
1034.4-123.12 = 910.28 g H2O or 0.91028 kg solvent.
Then 2.32 moles NH4Cl/0.91028 kg solvent =2.549 m which rounds to 2.55 m.
Check my thinking carefully,
2.32 moles NH4Cl = 2.32 x (53.5g/mol) = 124.12 g NH4Cl
mass of 1000 mL of the solution is 1000 x 1.0344 g/mL = 1034.4 g and 123.12 g is NH4Cl; therefore, the amount of water is
1034.4-123.12 = 910.28 g H2O or 0.91028 kg solvent.
Then 2.32 moles NH4Cl/0.91028 kg solvent =2.549 m which rounds to 2.55 m.
Check my thinking carefully,
Answered by
J
A solution is prepared by dissolving 23.7 g of Ca in 375 g of water. The density of the resulting solution is
density of 1.05 g/ml
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.