Asked by Hilavidpreet
The density of an aqueous solution containing 10% of ethanol (C2H5OH) by mass is 0.984 g/ml.
A) Calculate the molality of this solution.
B) Calculate its molarity.
C) What volume of the solution would contain 0.125 mol of ethanol.
A) Calculate the molality of this solution.
B) Calculate its molarity.
C) What volume of the solution would contain 0.125 mol of ethanol.
Answers
Answered by
DrBob222
10% means 10 g EtOH/100 g solution which is 10 g EtOH/(10 g EtOH + 90 g water).
A. 10 g is how many moles? moles = grams/molar mass.
m = moles/kg solvent.
Substitute moles from above. kg solvent is 0.090 kg.
B. molarity = moles/L soln.
moles you have from above.
The 10% soln has a mass of 100 grams. Use the density to convert 100 g to volume (which will be in mL), then convert to L and divide moles/L to arrive at molarity.
C. M x L = 0.125. You have M, solve for L.
A. 10 g is how many moles? moles = grams/molar mass.
m = moles/kg solvent.
Substitute moles from above. kg solvent is 0.090 kg.
B. molarity = moles/L soln.
moles you have from above.
The 10% soln has a mass of 100 grams. Use the density to convert 100 g to volume (which will be in mL), then convert to L and divide moles/L to arrive at molarity.
C. M x L = 0.125. You have M, solve for L.
Answered by
Hilavidpreet
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