Since the first and last terms are perfect squares, become suspicious and
test if it is perfect square.
sure enough, I get
(6f + 7)^2
36f^2+84f+49
Idk what to do?? Thanks for the help!
4 answers
36 and 49 are both perfect squares which makes me suspicious
(6 f +/- 7) (6 f +/- 7) ???
oh my 6*7 = 42 and twice that is 84, we have it made
(6 f+7)(6 f+7)
You did not say what is on the right. If it is 0 then
f = -7/6, -7/6 and that is the vertex
(6 f +/- 7) (6 f +/- 7) ???
oh my 6*7 = 42 and twice that is 84, we have it made
(6 f+7)(6 f+7)
You did not say what is on the right. If it is 0 then
f = -7/6, -7/6 and that is the vertex
thanks!! can you tell me how you got rid of the 84f? Since 36=6f and then the +7 represent 49.
(6 f+7)(6 f+7)
now let's do that multiplication the long way
6 f (6 f + 7) + 7 (6 f + 7) = 6f *6f + 6f*7 + 6f*7 + 7*7
= 36 f^2 + 42 f + 42 f + 49
= 36 f^2 + 84 f+ 49
see that 42 f + 42 f = 84 f?
now let's do that multiplication the long way
6 f (6 f + 7) + 7 (6 f + 7) = 6f *6f + 6f*7 + 6f*7 + 7*7
= 36 f^2 + 42 f + 42 f + 49
= 36 f^2 + 84 f+ 49
see that 42 f + 42 f = 84 f?