Question

What force would you have to exert on a 324 N trunk up a 19 degree inclined plane so that it would slide down the plane with a constant velocity? What would be the direction of the force? The coefficient of friction between the plane and the trunk is .322.

Answers

bobpursley
Break the weight of the trunk into two components, one down the plane, and one normal to it.

Forcedownplane=mg*sinTheta
Forcenormal=mg*cosTheta

Then, the force of friction is down, as motion is upward mu*mg*cosTheta

Summing forces up the plane:

F-mu*mg*cosTheta - mg*sinTheta=ma=0
solve for F. ma is zero because of zero acceleration (constant velocity)

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