Asked by Anonymous
What force would you have to exert on a 324 N trunk up a 19 degree inclined plane so that it would slide down the plane with a constant velocity? What would be the direction of the force? The coefficient of friction between the plane and the trunk is .322.
Answers
Answered by
bobpursley
Break the weight of the trunk into two components, one down the plane, and one normal to it.
Forcedownplane=mg*sinTheta
Forcenormal=mg*cosTheta
Then, the force of friction is down, as motion is upward mu*mg*cosTheta
Summing forces up the plane:
F-mu*mg*cosTheta - mg*sinTheta=ma=0
solve for F. ma is zero because of zero acceleration (constant velocity)
Forcedownplane=mg*sinTheta
Forcenormal=mg*cosTheta
Then, the force of friction is down, as motion is upward mu*mg*cosTheta
Summing forces up the plane:
F-mu*mg*cosTheta - mg*sinTheta=ma=0
solve for F. ma is zero because of zero acceleration (constant velocity)
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