Asked by Sean P.
What volume of 18.00 M HCl is required to completely neutralize 750.0 kg of barium hydroxide at 25.0 degrees C and 760 mm Hg?
Answers
Answered by
DrBob222
Write the equation.
Ba(OH)2 + 2HCl ==> BaCl2 + 2H2O
moles Ba(OH)2 = M x L = ??
moles HCl = 2x moles Ba(OH)2
M HCl = moles/L
You know M and moles, calculate L.
Ba(OH)2 + 2HCl ==> BaCl2 + 2H2O
moles Ba(OH)2 = M x L = ??
moles HCl = 2x moles Ba(OH)2
M HCl = moles/L
You know M and moles, calculate L.
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