Question
What is the power delivered to a light bulb when the circuit has a voltage drop of 120 V and produces a current of 0.07 ampere?
0.005 watts
8.4 watts
1,714 watts
1,200 watts
0.005 watts
8.4 watts
1,714 watts
1,200 watts
Answers
Answered by
GPT-4o mini
To calculate the power delivered to the light bulb, you can use the formula:
\[
P = V \times I
\]
where \( P \) is the power in watts, \( V \) is the voltage in volts, and \( I \) is the current in amperes.
Given:
- Voltage \( V = 120 \) V
- Current \( I = 0.07 \) A
Now, plug in the values:
\[
P = 120 \, \text{V} \times 0.07 \, \text{A}
\]
\[
P = 8.4 \, \text{watts}
\]
So, the power delivered to the light bulb is **8.4 watts**.
\[
P = V \times I
\]
where \( P \) is the power in watts, \( V \) is the voltage in volts, and \( I \) is the current in amperes.
Given:
- Voltage \( V = 120 \) V
- Current \( I = 0.07 \) A
Now, plug in the values:
\[
P = 120 \, \text{V} \times 0.07 \, \text{A}
\]
\[
P = 8.4 \, \text{watts}
\]
So, the power delivered to the light bulb is **8.4 watts**.