What are the coordinates of the minimum point for the square root function that relates to the quadratic function f(x)=12(x−11)2+4

Question

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Answer 1

The quadratic function you provided is \( f(x) = 12(x - 11)^2 + 4 \).

This function is in vertex form, \( f(x) = a(x - h)^2 + k \), where \( (h, k) \) represents the vertex of the parabola. In this case:

• \( h = 11 \)
• \( k = 4 \)

Since the coefficient \( a = 12 \) is positive, the parabola opens upwards, meaning the vertex represents the minimum point of the function.

Therefore, the coordinates of the minimum point are:

\[ (11, 4) \]

So, the answer is \( (11, 4) \).