Question

What are the coordinates of the minimum point for the square root function that relates to the quadratic function f(x)=12(x−11)2+4
?(1 point)
(
,
)

Answer 1

The quadratic function you provided is \( f(x) = 12(x - 11)^2 + 4 \).

This function is in vertex form, \( f(x) = a(x - h)^2 + k \), where \( (h, k) \) represents the vertex of the parabola. In this case:

- \( h = 11 \)
- \( k = 4 \)

Since the coefficient \( a = 12 \) is positive, the parabola opens upwards, meaning the vertex represents the minimum point of the function.

Therefore, the coordinates of the minimum point are:

\[
(11, 4)
\]

So, the answer is \( (11, 4) \).