What is the equation for the axis of symmetry on the parabola created by y=3(x−1)^2−12

Question

?(1 point)
x=_

Answer 1

The equation for the axis of symmetry of a parabola in the vertex form \(y = a(x-h)^2 + k\) is given by \(x = h\), where \((h, k)\) is the vertex of the parabola.

For the given equation:

\[ y = 3(x - 1)^2 - 12 \]

Here, \(h = 1\). Therefore, the axis of symmetry is:

\[ x = 1 \]

So the final answer is:

x = 1