What is the equation for the axis of symmetry on the parabola created by y=3(x−1)2−12 ?(1 point)

Question

x=

Answer 1

The equation for the axis of symmetry of a parabola in the vertex form \( y = a(x - h)^2 + k \) is given by the line \( x = h \), where \((h, k)\) is the vertex of the parabola.

For the given equation \( y = 3(x - 1)^2 - 12 \):

• The value of \( h \) (from \( (x - h) \)) is 1.
• Therefore, the equation of the axis of symmetry is:

\[ x = 1 \]