Question

I do not how to do this problem could some one help me please.

x+1/x+2-x^2+1/x^2-x-6

Answer 1

You will have to re-type it using brackets to establish the proper order of operations.

The way it stands it means
x + (1/x) - x^2 + (1/x^2) - x - 6

I am sure that is not what you meant

could it be
(x+1)/(x+2-x^2) + 1/(x^2-x-6) ?

Answer 2

x+1 over x+2 minus x^2+1 over x^2 minus x- minus 6
this is the right way

Answer 3

ok, I read that as

(x+1)/(x+2) - (x^2 + 1)/(x^2 - x - 6)
= (x+1)/(x+2) - (x^2 + 1)/[(x-3)(x+2)]
(so the LCD is (x-3)(x+2) )

= (x+1)(x+2)/[(x-3)(x+2)] - (x^2 + 1)/[(x-3)(x+2)]
= (x^2 + 3x + 2 - x^2 - 1)/[(x-3)(x+2)]
= (3x-1)/[(x-3)(x+2)]