Asked by Libby
Can someone make sure I did this write!
What is the molar change in enthalpy when 100 g of ice is heated from -18.2 C to -72 C (Cp = 37.4 J/K*mol)
100g of ice = 100 g/-18.2 C = 5.56 mol
5.56 mol * 37.4 J/K * mol * 53.8 K = 1118 J
What is the molar change in enthalpy when 100 g of ice is heated from -18.2 C to -72 C (Cp = 37.4 J/K*mol)
100g of ice = 100 g/-18.2 C = 5.56 mol
5.56 mol * 37.4 J/K * mol * 53.8 K = 1118 J
Answers
Answered by
DrBob222
I would have used 100 g/18.015 = 5.55 moles (You seem to have picked up the 18.2 from the degrees C).
Then 5.55 x 37.4 x 53.8 = 11,167 Joules.
Did you just drop the last digit?
Then 5.55 x 37.4 x 53.8 = 11,167 Joules.
Did you just drop the last digit?
Answered by
Libby
THANK YOU! yes, i got 11180, i see what I did wrong.
Answered by
DrBob222
By the way, I'm a little confused with the statement that ice is heated to move it from -18.2 to -72.
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