Asked by Matt
Find the derivative if x^3 + 4xy^2 - y^4 = 7
Answers
Answered by
Count Iblis
x^3 + 4xy^2 - y^4 = 7 --->
d[x^3 + 4xy^2 - y^4 ] = 0 ----->
3x^2 dx + 4y^2 dx + 8yx dy -4 y^3 dy = 0
3x^2 dx + 4y^2 dx =(4y^3 - 8yx) dy -->
3x^2+ 4y^2=(4y^3 - 8yx) dy/dx ---->
dy/dx = (3x^2+ 4y^2)/(4y^3 - 8yx)
d[x^3 + 4xy^2 - y^4 ] = 0 ----->
3x^2 dx + 4y^2 dx + 8yx dy -4 y^3 dy = 0
3x^2 dx + 4y^2 dx =(4y^3 - 8yx) dy -->
3x^2+ 4y^2=(4y^3 - 8yx) dy/dx ---->
dy/dx = (3x^2+ 4y^2)/(4y^3 - 8yx)
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