To find which two expressions are equivalent to the given expression \( 4(x+3)−10+6x \), we first need to simplify the original expression:
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Distribute the 4 in \( 4(x + 3) \): \[ 4 \cdot x + 4 \cdot 3 = 4x + 12 \]
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Substitute back into the expression: \[ 4x + 12 - 10 + 6x \]
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Combine like terms: \[ (4x + 6x) + (12 - 10) = 10x + 2 \]
Now, we are looking for expressions that simplify to \( 10x + 2 \):
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Check \( 4x + 12 - 10 + 6x \):
- We already simplified this in the steps above to get \( 10x + 2 \).
- This is equivalent.
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Check \( 10x - 7 \):
- This does not match \( 10x + 2 \).
- This is not equivalent.
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Check \( 2(8x + 1) \):
- Distributing gives \( 2 \cdot 8x + 2 \cdot 1 = 16x + 2 \).
- This does not match \( 10x + 2 \).
- This is not equivalent.
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Check \( 2(5x + 1) \):
- Distributing gives \( 2 \cdot 5x + 2 \cdot 1 = 10x + 2 \).
- This is equivalent.
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Check \( -2x - 7 \):
- This is clearly not equivalent to \( 10x + 2 \).
- This is not equivalent.
Thus, the two expressions that are equivalent to the given expression \( 4(x+3)−10+6x \) are:
- \( 4x + 12 - 10 + 6x \)
- \( 2(5x + 1) \)