Asked by Christine

The amount of light emitted from a battery indicator bulb pulses while the battery is charging. This can be modeled by the equation y = 60+60sin[(pi/4)t] , where y is the lumens emitted from the bulb and t is the number of seconds since the beginning of a pulse. At what time will the amount of light emitted be equal to 110 lumens?
Answered by Reiny
mhh, aren't we just solving
60 + 60sin[(π/4)t] = 110 ?

sin[(π/4)t] = .833333
make sure your calculator is set to radians
[(π/4)t] = .98511
t = .....

let me know what you got
Answered by Christine
im stupid
Answered by Christine
1.25 is what i got
Answered by Reiny
correct!
good job

Answered by Christine
THANK YOU!
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