To determine which ordered pair is part of the solution set for the equation \( y = x^2 + 4x - 5 \), we need to evaluate each ordered pair by substituting the x-value into the equation and checking if the corresponding y-value is correct.
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For \( (0, -5) \): \[ y = 0^2 + 4(0) - 5 = 0 + 0 - 5 = -5 \] This is a solution.
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For \( (5, 0) \): \[ y = 5^2 + 4(5) - 5 = 25 + 20 - 5 = 40 \] This is not a solution since \( y \) should be 0.
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For \( (-9, -2) \): \[ y = (-9)^2 + 4(-9) - 5 = 81 - 36 - 5 = 40 \] This is not a solution since \( y \) should be -2.
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For \( (0, 1) \): \[ y = 0^2 + 4(0) - 5 = 0 + 0 - 5 = -5 \] This is not a solution since \( y \) should be 1.
Based on the evaluations, the only ordered pair that is part of the solution set for the equation \( y = x^2 + 4x - 5 \) is:
(0, -5)