Asked by Fred
A 2.28 m solution of the solute formic acid dissolved in the solvent H2O is available. Calculate the mass ( kg ) of the solution that must be taken to obtain 12.40 mol of formic acid.
Correct Answer = 6.01
Molar Mass (g/mol):
HCO2H 46.03
H2O 18.015
Density ( g/mL ):
HCO2H 1.220
H2O 0.9982
Can someone please explain to me how to come to the answer above.
Correct Answer = 6.01
Molar Mass (g/mol):
HCO2H 46.03
H2O 18.015
Density ( g/mL ):
HCO2H 1.220
H2O 0.9982
Can someone please explain to me how to come to the answer above.
Answers
Answered by
DrBob222
m = moles solute/kg solvent
2.28 = 12.40/kg solvent.
Solve for kg solvent, then add the equivalent of 12.40 moles HCOOH (at 46.03 g/mole) and add to kg solvent to obtain total mass of solution. I get 6.009 which rounds to 6.01 kg.
2.28 = 12.40/kg solvent.
Solve for kg solvent, then add the equivalent of 12.40 moles HCOOH (at 46.03 g/mole) and add to kg solvent to obtain total mass of solution. I get 6.009 which rounds to 6.01 kg.
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