distance = 1/2 gt^2 Solve for time it takes for the penny to reach the ground.
Then distance = 1/2(Vinitial + Vfinal)t.
Vinitial is zero. You know distance and t, solve for Vfinal.
Then distance = 1/2(Vinitial + Vfinal)t.
Vinitial is zero. You know distance and t, solve for Vfinal.
t^2=2d/g
t^2=2(370)/9.8
t^2=75.51
t=8.6 second
v2=v1+gt
v2=0+(9.8m/s^2)(8.6s)
v2=84.3m/s
The first step is to find the time it takes for the penny to fall. We can use the equation for free fall motion:
h = (1/2) * g * t^2
Where:
h is the height (370 m)
g is the acceleration due to gravity (9.8 m/s^2)
t is the time it takes to fall
Rearranging the equation to solve for t:
t^2 = (2 * h) / g
t = sqrt((2 * h) / g)
t = sqrt((2 * 370 m) / 9.8 m/s^2)
t ≈ 8.6 s
Now that we know the time of fall, we can find the velocity using the equation:
v = g * t
Substituting the known values:
v = 9.8 m/s^2 * 8.6 s ≈ 84.28 m/s
Therefore, the penny will strike the ground with a velocity of approximately 84.28 m/s.