Question

if a penny is dropped from the top of a 320 ft. building, how fast will it be moving when it hits the ground?

v2 = u2 + 2gH,
Here, u = initial velocity = 0
v = final velocity
g = 32ft/s2
H= 320ft
So, v2= 0 + 2 × 32 × 320
or,. v = ✓(2×32×32×2×5)
or, v = 64✓5 ft/s
is this correct?

Answer 1

looks good