To model the decline of the antelope herd, we can use the exponential decay formula:
\[ P(t) = P_0 \cdot e^{kt} \]
where:
- \( P(t) \) is the population at time \( t \),
- \( P_0 \) is the initial population,
- \( k \) is the decay constant,
- \( t \) is the time in years,
- \( e \) is the base of the natural logarithm.
However, since the problem specifies a constant percentage decrease, we can use a slightly different formula:
\[ P(t) = P_0 (1 - r)^t \]
where:
- \( r \) is the rate of decay expressed as a decimal.
For this specific problem:
- \( P_0 = 570 \) (the initial population),
- \( r = 0.06 \) (the decay rate of 6%),
- and \( t = 10 \) years.
So, our function becomes:
\[ P(t) = 570 (1 - 0.06)^{t} \] \[ P(t) = 570 (0.94)^{t} \]
Now we can calculate the population after 10 years:
\[ P(10) = 570 (0.94)^{10} \]
Calculating \( (0.94)^{10} \):
\[ (0.94)^{10} \approx 0.527 \]
Now multiply that by 570:
\[ P(10) \approx 570 \times 0.527 \] \[ P(10) \approx 300.39 \]
Rounding to the nearest whole number:
After 10 years, there will be approximately 300 antelopes in the herd.