To model the decline of the antelope population using an exponential decay function, we can use the formula:
\[ P(t) = P_0 \cdot e^{kt} \]
where:
- \( P(t) \) is the population at time \( t \),
- \( P_0 \) is the initial population (570 antelopes),
- \( k \) is the decay constant,
- \( t \) is the time in years,
- \( e \) is the base of the natural logarithm.
Since the population is declining at a rate of 6% per year, we have:
\[ k = -0.06 \]
Now, substituting \( P_0 = 570 \) and \( k = -0.06 \) into the formula gives us:
\[ P(t) = 570 \cdot e^{-0.06t} \]
Now we want to find the population after 10 years, so we set \( t = 10 \):
\[ P(10) = 570 \cdot e^{-0.06 \times 10} \]
Calculating \( -0.06 \times 10 \):
\[ -0.06 \times 10 = -0.6 \]
Thus, we have:
\[ P(10) = 570 \cdot e^{-0.6} \]
Now we compute \( e^{-0.6} \):
\[ e^{-0.6} \approx 0.5488 \]
Now substituting back into the equation:
\[ P(10) \approx 570 \cdot 0.5488 \approx 312.696 \]
Rounding to the nearest whole number, we find:
\[ P(10) \approx 313 \]
Therefore, after 10 years, there will be approximately 313 antelopes in the herd.