Asked by bots lover
Solve the system of equations.
3x+y=2
7x−4y=30
(1 point)
Responses
(2, −4)
left parenthesis 2 comma negative 4 right parenthesis
(12, 12)
left parenthesis start fraction 1 over 2 end fraction comma start fraction 1 over 2 end fraction right parenthesis
(2, −2)
left parenthesis 2 comma negative 2 right parenthesis
(−2, 8)
3x+y=2
7x−4y=30
(1 point)
Responses
(2, −4)
left parenthesis 2 comma negative 4 right parenthesis
(12, 12)
left parenthesis start fraction 1 over 2 end fraction comma start fraction 1 over 2 end fraction right parenthesis
(2, −2)
left parenthesis 2 comma negative 2 right parenthesis
(−2, 8)
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve the system of equations:
1. \(3x + y = 2\) (Equation 1)
2. \(7x - 4y = 30\) (Equation 2)
We can use substitution or elimination. Let's use substitution with Equation 1.
From Equation 1, solve for \(y\):
\[y = 2 - 3x\]
Now, substitute \(y\) in Equation 2:
\[7x - 4(2 - 3x) = 30\]
Now distribute the \(-4\):
\[7x - 8 + 12x = 30\]
Combine like terms:
\[19x - 8 = 30\]
Add 8 to both sides:
\[19x = 38\]
Now, divide by 19:
\[x = 2\]
Now that we have \(x\), substitute back into the expression for \(y\):
\[y = 2 - 3(2)\]
\[y = 2 - 6\]
\[y = -4\]
Thus, the solution to the system of equations is:
\((2, -4)\)
Therefore, the correct response is:
\((2, -4)\)
1. \(3x + y = 2\) (Equation 1)
2. \(7x - 4y = 30\) (Equation 2)
We can use substitution or elimination. Let's use substitution with Equation 1.
From Equation 1, solve for \(y\):
\[y = 2 - 3x\]
Now, substitute \(y\) in Equation 2:
\[7x - 4(2 - 3x) = 30\]
Now distribute the \(-4\):
\[7x - 8 + 12x = 30\]
Combine like terms:
\[19x - 8 = 30\]
Add 8 to both sides:
\[19x = 38\]
Now, divide by 19:
\[x = 2\]
Now that we have \(x\), substitute back into the expression for \(y\):
\[y = 2 - 3(2)\]
\[y = 2 - 6\]
\[y = -4\]
Thus, the solution to the system of equations is:
\((2, -4)\)
Therefore, the correct response is:
\((2, -4)\)
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