Question
Graph the inequality on the axes below.
2, x, minus, 5, y, is less than or equal to, minus, 10
2x−5y≤−10
Can you pls tell me the 2 points also they have to intercept the line so were the points on the lines are i need points outside it that go through them and pls tell me witch side is getting shaded
The points are based on the ineguality and slope
2, x, minus, 5, y, is less than or equal to, minus, 10
2x−5y≤−10
Can you pls tell me the 2 points also they have to intercept the line so were the points on the lines are i need points outside it that go through them and pls tell me witch side is getting shaded
The points are based on the ineguality and slope
Answers
Answered by
GPT-4o mini
To graph the inequality \(2x - 5y \leq -10\), we first need to find the boundary line by setting the equation to an equality:
\[
2x - 5y = -10.
\]
### Step 1: Find the intercepts
1. **x-intercept**: Set \(y = 0\):
\[
2x - 5(0) = -10 \implies 2x = -10 \implies x = -5.
\]
So, the x-intercept is \((-5, 0)\).
2. **y-intercept**: Set \(x = 0\):
\[
2(0) - 5y = -10 \implies -5y = -10 \implies y = 2.
\]
So, the y-intercept is \((0, 2)\).
### Step 2: Plot the line
Now we can plot the line with these intercepts:
- The point \((-5, 0)\) on the x-axis.
- The point \((0, 2)\) on the y-axis.
### Step 3: Determine the line type
Since the inequality is "less than or equal to" (\(\leq\)), we will draw a solid line through the intercept points since points on the line are included in the solution set.
### Step 4: Find points to test the inequality
To determine which side of the line to shade, we can test a point not on the line. A common choice is the origin \((0, 0)\):
Substitute \(x = 0\) and \(y = 0\) into the original inequality:
\[
2(0) - 5(0) \leq -10 \implies 0 \leq -10.
\]
This statement is false, so we do **not** shade the region that includes \((0, 0)\). Therefore, we will shade the opposite side of the line.
### Step 5: Identify points outside the line
You can choose any points in the shaded region as \(x\) and \(y\) values are less than the line. Here are two examples of points:
1. Point \((-6, 0)\):
\[
2(-6) - 5(0) = -12 \leq -10 \quad \text{(True)}
\]
2. Point \((-5, 1)\):
\[
2(-5) - 5(1) = -10 - 5 = -15 \leq -10 \quad \text{(True)}
\]
### Conclusion
- The points you can use as examples are: **\((-6, 0)\) and \((-5, 1)\)**.
- The region below the line \(2x - 5y = -10\) will be shaded, as this represents the solution set of the inequality \(2x - 5y ≤ -10\).
Feel free to plot these points and the line on a graph to visualize the solution!
\[
2x - 5y = -10.
\]
### Step 1: Find the intercepts
1. **x-intercept**: Set \(y = 0\):
\[
2x - 5(0) = -10 \implies 2x = -10 \implies x = -5.
\]
So, the x-intercept is \((-5, 0)\).
2. **y-intercept**: Set \(x = 0\):
\[
2(0) - 5y = -10 \implies -5y = -10 \implies y = 2.
\]
So, the y-intercept is \((0, 2)\).
### Step 2: Plot the line
Now we can plot the line with these intercepts:
- The point \((-5, 0)\) on the x-axis.
- The point \((0, 2)\) on the y-axis.
### Step 3: Determine the line type
Since the inequality is "less than or equal to" (\(\leq\)), we will draw a solid line through the intercept points since points on the line are included in the solution set.
### Step 4: Find points to test the inequality
To determine which side of the line to shade, we can test a point not on the line. A common choice is the origin \((0, 0)\):
Substitute \(x = 0\) and \(y = 0\) into the original inequality:
\[
2(0) - 5(0) \leq -10 \implies 0 \leq -10.
\]
This statement is false, so we do **not** shade the region that includes \((0, 0)\). Therefore, we will shade the opposite side of the line.
### Step 5: Identify points outside the line
You can choose any points in the shaded region as \(x\) and \(y\) values are less than the line. Here are two examples of points:
1. Point \((-6, 0)\):
\[
2(-6) - 5(0) = -12 \leq -10 \quad \text{(True)}
\]
2. Point \((-5, 1)\):
\[
2(-5) - 5(1) = -10 - 5 = -15 \leq -10 \quad \text{(True)}
\]
### Conclusion
- The points you can use as examples are: **\((-6, 0)\) and \((-5, 1)\)**.
- The region below the line \(2x - 5y = -10\) will be shaded, as this represents the solution set of the inequality \(2x - 5y ≤ -10\).
Feel free to plot these points and the line on a graph to visualize the solution!
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