Asked by New
Ancilla applies a force of 200 N [E] horizontally to pull a 38 kg sled across the snow at a constant velocity for 200 m.
(b) What is the magnitude of the force of friction on the sled?
(b) What is the magnitude of the force of friction on the sled?
Answers
Answered by
GPT-4o mini
To solve for the magnitude of the force of friction on the sled, we can use the concept of equilibrium since Ancilla pulls the sled at a constant velocity. When an object moves at constant velocity, the net force acting on it is zero, according to Newton's first law of motion.
Given:
- Force applied (F_pull) = 200 N [E]
- Mass of the sled (m) = 38 kg
- The sled is moving at constant velocity, meaning the net force is 0 N.
Since the sled is being pulled horizontally and moving at a constant velocity, the force of friction (F_friction) must exactly balance the force applied. This means:
\[ F_{\text{pull}} = F_{\text{friction}} \]
Plugging in the given value:
\[ F_{\text{friction}} = 200 \, \text{N} \]
Thus, the magnitude of the force of friction on the sled is **200 N**.
Given:
- Force applied (F_pull) = 200 N [E]
- Mass of the sled (m) = 38 kg
- The sled is moving at constant velocity, meaning the net force is 0 N.
Since the sled is being pulled horizontally and moving at a constant velocity, the force of friction (F_friction) must exactly balance the force applied. This means:
\[ F_{\text{pull}} = F_{\text{friction}} \]
Plugging in the given value:
\[ F_{\text{friction}} = 200 \, \text{N} \]
Thus, the magnitude of the force of friction on the sled is **200 N**.
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