Question
A car applies a force of 36.8 Newtons for a 668-meter loop; what was the work done?(1 point)
Responses
24,600 J
24,600 J
705 J
705 J
18.2 J
18.2 J
0 J
0 J
Responses
24,600 J
24,600 J
705 J
705 J
18.2 J
18.2 J
0 J
0 J
Answers
GPT-4o mini
To calculate the work done when a force is applied over a distance, we can use the formula:
\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]
where:
- Work is measured in joules (J)
- Force is measured in newtons (N)
- Distance is measured in meters (m)
- \( \theta \) is the angle between the force and the direction of motion.
If the force is applied in the same direction as the motion, \( \theta = 0 \) degrees and \( \cos(0) = 1 \).
In your case:
- Force (F) = 36.8 N
- Distance (d) = 668 m
Assuming the force is applied in the direction of movement, we can calculate work:
\[ \text{Work} = 36.8 \, \text{N} \times 668 \, \text{m} \]
\[ \text{Work} = 24,605.4 \, \text{J} \]
Rounded to three significant figures, this is approximately:
\[ \text{Work} \approx 24,600 \, \text{J} \]
Thus, the correct response is:
**24,600 J**
\[ \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) \]
where:
- Work is measured in joules (J)
- Force is measured in newtons (N)
- Distance is measured in meters (m)
- \( \theta \) is the angle between the force and the direction of motion.
If the force is applied in the same direction as the motion, \( \theta = 0 \) degrees and \( \cos(0) = 1 \).
In your case:
- Force (F) = 36.8 N
- Distance (d) = 668 m
Assuming the force is applied in the direction of movement, we can calculate work:
\[ \text{Work} = 36.8 \, \text{N} \times 668 \, \text{m} \]
\[ \text{Work} = 24,605.4 \, \text{J} \]
Rounded to three significant figures, this is approximately:
\[ \text{Work} \approx 24,600 \, \text{J} \]
Thus, the correct response is:
**24,600 J**