How many grams of glacial acetic acid should be used to make 250 mL of 2.00 M acetic acid? Show all your work.

Mol wgt. of acetic acid is 60grams in 1litre is 1M for 2M dissolve 120gram of glacial acetic acid in 1litre toget d required volume of 250ml divide1litre by 4 do the same to 120grams thus weigh only 30g of glacial acetic acid in make up to250ml mark this will give the required 2M

To calculate the number of grams of glacial acetic acid needed to make 250 mL of 2.00 M acetic acid, we need to follow these steps:

Step 1: Convert the volume in milliliters to liters.
250 mL = 250/1000 = 0.25 L

Step 2: Use the formula for molarity to calculate the number of moles of acetic acid.
Molarity (M) = moles of solute / volume of solution in liters
2.00 M = moles of acetic acid / 0.25 L

Rearranging the formula, we get:
moles of acetic acid = Molarity (M) x volume of solution in liters
moles of acetic acid = 2.00 M x 0.25 L = 0.50 moles

Step 3: Use the molar mass of acetic acid to calculate the number of grams needed.
The molar mass of acetic acid (CH3COOH) is:
(1 x 12.01 g/mol) + (2 x 1.008 g/mol) + (4 x 16.00 g/mol) = 60.052 g/mol

The number of grams of acetic acid needed can be calculated using the formula:
grams = moles x molar mass
grams = 0.50 moles x 60.052 g/mol ≈ 30.03 g

Therefore, you would need approximately 30.03 grams of glacial acetic acid to make 250 mL of 2.00 M acetic acid.

To calculate the number of grams of glacial acetic acid needed to make a specific concentration of acetic acid solution, we need to know the molecular weight of acetic acid. The chemical formula for acetic acid is CH3COOH, and its molecular weight is 60.05 g/mol.

To calculate the number of moles of acetic acid required, we can use the formula:

moles of solute (acetic acid) = concentration (M) × volume (L)

Given that the desired concentration of acetic acid is 2.00 M and the volume is 0.250 L (since 250 mL is equivalent to 0.250 L), we can substitute these values into the formula:

moles of acetic acid = 2.00 M × 0.250 L = 0.500 mol

Since we now know the moles of acetic acid required, we can calculate the mass (in grams) using the formula:

mass (g) = moles × molecular weight

Substituting the values, we get:

mass of acetic acid = 0.500 mol × 60.05 g/mol = 30.025 g

Therefore, you would need approximately 30.025 grams of glacial acetic acid to make 250 mL of 2.00 M acetic acid solution.