Question

Solve the system of two equations using substitution
Y = 2 + 3x
4x - 3y = -16

Answer 1

Solve these pls
2x + 6y = -18
x = 5y - 1

Answer 2

To solve the system of equations using substitution, we have the following two equations:

1. \( y = 2 + 3x \)
2. \( 4x - 3y = -16 \)

We will substitute the expression for \( y \) from the first equation into the second equation.

### Step 1: Substitute \( y \)

Replace \( y \) in the second equation with \( 2 + 3x \):
\[
4x - 3(2 + 3x) = -16
\]

### Step 2: Distribute and simplify

Now distribute the \(-3\) through \( (2 + 3x) \):
\[
4x - 6 - 9x = -16
\]

Combine like terms:
\[
-5x - 6 = -16
\]

### Step 3: Isolate \( x \)

Now add \( 6 \) to both sides:
\[
-5x = -10
\]

Divide both sides by \(-5\):
\[
x = 2
\]

### Step 4: Find \( y \)

Now substitute \( x = 2 \) back into the first equation to find \( y \):
\[
y = 2 + 3(2)
\]
\[
y = 2 + 6 = 8
\]

### Step 5: Solution

The solution to the system of equations is:
\[
\boxed{(2, 8)}
\]