To solve the system of equations using elimination with multiplication, we first need to identify the equations given. The first equation you provided seems to be incomplete or misrepresented as "AT - 0". Assuming it was meant to say \( x - 0 = 0 \) or another standard form, we'll look at the second equation:
\[ -2x + 4y = 30 \]
However, since there seems to be confusion, let's tackle this one equation at a time.
If we take the equation \( -2x + 4y = 30 \), we can simplify and analyze it properly.
Divide the entire equation by 2:
\[ -x + 2y = 15 \]
Now, observing your list of options, it seems you might be asking for a solution to the equation, or you may have another equation that hasn't been provided.
For the interpretations, I can derive potential terminations based on the options for \( (x, y) \):
- \( (-3, 6) \)
- \( (-33, -9) \)
- \( (3, 9) \)
- \( (-21, -6) \)
We substitute each option into the equation \( -x + 2y = 15 \):
-
For \( (-3, 6) \): \[ -(-3) + 2(6) = 3 + 12 = 15 \quad \text{(Satisfies the equation)} \]
-
For \( (-33, -9) \): \[ -(-33) + 2(-9) = 33 - 18 = 15 \quad \text{(Does not satisfy)} \]
-
For \( (3, 9) \): \[ -(3) + 2(9) = -3 + 18 = 15 \quad \text{(Satisfies the equation)} \]
-
For \( (-21, -6) \): \[ -(-21) + 2(-6) = 21 - 12 = 9 \quad \text{(Does not satisfy)} \]
So the solutions to the equation \( -2x + 4y = 30 \) are \( (-3, 6) \) and \( (3, 9) \).
Please provide the first equation correctly if there’s another term to compare. Would you need assistance finding them or clarifying the conditions under which to solve the system?