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Given the square root function, y=1/2√x+3−9, what is the y-value when x=13

Responses

−7

−5

2

−1

1 answer

To find the y-value when \( x = 13 \) for the function \( y = \frac{1}{2} \sqrt{x + 3} - 9 \), we will substitute \( x \) with 13 and calculate \( y \).

  1. Substitute \( x = 13 \) into the function: \[ y = \frac{1}{2} \sqrt{13 + 3} - 9 \]

  2. Simplify inside the square root: \[ y = \frac{1}{2} \sqrt{16} - 9 \]

  3. Calculate the square root: \[ y = \frac{1}{2} \times 4 - 9 \]

  4. Perform the multiplication: \[ y = 2 - 9 \]

  5. Subtract: \[ y = -7 \]

Thus, the y-value when \( x = 13 \) is \( -7 \). Therefore, the correct response is:

−7