Question

Given the square root function, y=1/2√x+3−9, what is the y-value when x=13

Responses

−7

−5

2

−1

Answer 1

To find the y-value when \( x = 13 \) for the function \( y = \frac{1}{2} \sqrt{x + 3} - 9 \), we will substitute \( x \) with 13 and calculate \( y \).

1. Substitute \( x = 13 \) into the function:
\[
y = \frac{1}{2} \sqrt{13 + 3} - 9
\]

2. Simplify inside the square root:
\[
y = \frac{1}{2} \sqrt{16} - 9
\]

3. Calculate the square root:
\[
y = \frac{1}{2} \times 4 - 9
\]

4. Perform the multiplication:
\[
y = 2 - 9
\]

5. Subtract:
\[
y = -7
\]

Thus, the y-value when \( x = 13 \) is \( -7 \). Therefore, the correct response is:

**−7**