given the square root function , y=1/2 sq root x + 3 - 9, what is the y-value when x = 13 ?

Answer 1

To find the y-value when \( x = 13 \) for the function \( y = \frac{1}{2} \sqrt{x} + 3 - 9 \), we will substitute \( x \) with 13 and simplify:

1. Substitute \( x = 13 \):

\[ y = \frac{1}{2} \sqrt{13} + 3 - 9 \]

2. Calculate \( 3 - 9 \):

\[ 3 - 9 = -6 \]

3. Now, substitute this back into the equation:

\[ y = \frac{1}{2} \sqrt{13} - 6 \]

4. Calculate \( \sqrt{13} \). The square root of 13 is approximately \( 3.60555 \).

5. Therefore:

\[ \frac{1}{2} \sqrt{13} \approx \frac{1}{2} \times 3.60555 \approx 1.802775 \]

6. Now, substitute this back into the equation for \( y \):

\[ y \approx 1.802775 - 6 \approx -4.197225 \]

So the approximate value of \( y \) when \( x = 13 \) is:

\[ y \approx -4.2 \]

In conclusion, the y-value when \( x = 13 \) is approximately \(-4.2\).