Question

What is the starting value in the equation f(x)=11(1.7)x−1
?(1 point)
The starting value is
.

Answer 1

In the equation \( f(x) = 11(1.7)^{x-1} \), the starting value can be found by evaluating the function at \( x = 1 \).

Let's calculate \( f(1) \):

\[
f(1) = 11(1.7)^{1-1} = 11(1.7)^0 = 11 \cdot 1 = 11
\]

So, the starting value is \( 11 \).