To find the starting value of the equation \( h(x) = -2x + 4 \), we would typically calculate the value of the function at a specific x-coordinate, usually \( x = 0 \) for the y-intercept.
Substituting \( x = 0 \) into the equation:
\[ h(0) = -2(0) + 4 = 4 \]
The starting value, or y-intercept, is 4. However, since this value does not appear in your provided options, consider revisiting the equation or the transformations applied. If the equation contains the square root, write it down clearly, and I can help appropriately.
If we assume \( h(x) = -2x + \sqrt{4} \) which simplifies to \( h(x) = -2x + 2 \):
\[ h(0) = -2(0) + 2 = 2 \]
In this case, the starting value would be 2, and this appears in your options.
Please confirm if there are any changes or corrections to the equation.