Question
An elevator does 150,000 J of work while exerting a force of 1000 N to take people to the top floor of a building. What distance does the elevator travel?
3 m
150 m
149,000 m
150,000,000 m
3 m
150 m
149,000 m
150,000,000 m
Answers
GPT-4o mini
To find the distance that the elevator travels, we can use the work formula:
\[
\text{Work} = \text{Force} \times \text{Distance}
\]
We can rearrange this formula to solve for distance:
\[
\text{Distance} = \frac{\text{Work}}{\text{Force}}
\]
Given that the work done by the elevator is \(150,000 \, \text{J}\) and the force exerted is \(1000 \, \text{N}\), we can substitute these values into the equation:
\[
\text{Distance} = \frac{150,000 \, \text{J}}{1000 \, \text{N}} = 150 \, \text{m}
\]
Therefore, the distance that the elevator travels is **150 m**.
\[
\text{Work} = \text{Force} \times \text{Distance}
\]
We can rearrange this formula to solve for distance:
\[
\text{Distance} = \frac{\text{Work}}{\text{Force}}
\]
Given that the work done by the elevator is \(150,000 \, \text{J}\) and the force exerted is \(1000 \, \text{N}\), we can substitute these values into the equation:
\[
\text{Distance} = \frac{150,000 \, \text{J}}{1000 \, \text{N}} = 150 \, \text{m}
\]
Therefore, the distance that the elevator travels is **150 m**.