You found that after 10 minutes, Tank A and Tank B will have the same amount of water. How much water will each tank have at that time? Solve on paper, then enter your answer on Zearn.

Question

Liters in Tank A after t minutes:
380+(−9t)
Liters in Tank B after t minutes:
420+(−13t)
After 10 minutes, Tank A and Tank B will each have
liters of water.

Answer 1

To find out how much water will be in each tank after 10 minutes, we need to substitute \( t = 10 \) into the equations for both tanks.

1. For Tank A, the amount of water after \( t \) minutes is given by: \[ \text{Liters in Tank A} = 380 + (-9t) = 380 - 9t \]

   Substituting \( t = 10 \): \[ \text{Liters in Tank A} = 380 - 9(10) = 380 - 90 = 290 \text{ liters} \]

2. For Tank B, the amount of water after \( t \) minutes is given by: \[ \text{Liters in Tank B} = 420 + (-13t) = 420 - 13t \]

   Substituting \( t = 10 \): \[ \text{Liters in Tank B} = 420 - 13(10) = 420 - 130 = 290 \text{ liters} \]

Both tanks will have the same amount of water after 10 minutes, which is 290 liters.

Thus, after 10 minutes, Tank A and Tank B will each have 290 liters of water.